Given the following triangle, solve for angle X.

Question

anonymous · Answer

attachment

akashdeepdeb · Answer

Whta kind of file is this?

goformit100 · Answer

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anonymous · Answer

I don't know I thought I saved it as a Jpeg but I can't open it either.
Hold on.

anonymous · Answer

what is x? if it is |YZ| then
x^2 + 3.5^2 = 4.6^2
so$$x = \sqrt{4.6^2-3.5^2} = 8.91$$

anonymous · Answer

attachment

anonymous · Answer

8.91 isn't a possible answer

anonymous · Answer

x = arccos (3.5/4.6) = 40.46 degrees

anonymous · Answer

So you used cosine?

anonymous · Answer

No, i used arccosine. inverse of the cosine. it takes the ratio of 2 sides and gives you the angle

akashdeepdeb · Answer

Use trigonometry here @TaylorTypo 
Use cosine of x because cosine = adjacent/hypotenuse
                                                  = 3.5/4.6
                                                  = 35/46
So cos x = 35/46
x = cos ^-1 (35/46) [Calculate]

That should be your answer!! :D

Understood? :)

akashdeepdeb · Answer

And yeah
Use Google Chrome! :P

anonymous · Answer

Ooh. I forgot to move the decimal point haha. Thanks!

akashdeepdeb · Answer

:)