I-4XI=32
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|a| = a |-a| = a so |-4x| = 32 is nothing but 4x = 32
\[\left| x \right|=x if x>0, \left| x \right|=-x ,if x<0\] solve taking both cases.
consider x=-4X from the constraints provided |x| = x if x is positive |x| = -x if x is negative since x is negative in our case we follow the second case so |x| = -x which implies |-4X| = - (-4X) = 4X consequently we obtain the equation 4X = 32 upon multiplying both sides by 1/4 we obtain the result X=32/4 or X=8
\[\left| x \right|=a,x=\pm a\] \[\left| -4x \right|=32,-4x=\pm 32,x=\pm 8\]
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