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HELP PLEASE!! MEDALS WILL BE GIVEN!! Express the solutions for x as Logarithms: 10^2x-5(10^x) +6 = 0
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Maybe a substitution will clear things up: let \(y=10^x\): \[10^{2x}-5(10^x)+6=0~~\iff~~y^2-5y+6=0\]
yea but i have to change it into logarithmic form
actually nm...i got it thank you :)
yw
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