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f(x)= { x^2 , x cannot = 2 and 2, x=2} find f(2), f(x) when x approaches 2- when 2+, and f(x) when x approaches 2
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what are you stuck on?
replace \(x\) by \(2\) and see what you get
will f(2) =2?
yep
i got 4?
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for the limits?
yes
you got it
so both limits are 4 which means when x approaches 2 its 4 too?
you're on fire!
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omg that's what I got but I wasn't sure lol
sounds like you're doing just fine!
thank you so much:)
you're welcome!
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