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Mathematics 23 Online
OpenStudy (anonymous):

f(x)= { x^2 , x cannot = 2 and 2, x=2} find f(2), f(x) when x approaches 2- when 2+, and f(x) when x approaches 2

OpenStudy (anonymous):

what are you stuck on?

OpenStudy (anonymous):

replace \(x\) by \(2\) and see what you get

OpenStudy (anonymous):

will f(2) =2?

OpenStudy (anonymous):

yep

OpenStudy (anonymous):

i got 4?

OpenStudy (anonymous):

for the limits?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

you got it

OpenStudy (anonymous):

so both limits are 4 which means when x approaches 2 its 4 too?

OpenStudy (anonymous):

you're on fire!

OpenStudy (anonymous):

omg that's what I got but I wasn't sure lol

OpenStudy (anonymous):

sounds like you're doing just fine!

OpenStudy (anonymous):

thank you so much:)

OpenStudy (anonymous):

you're welcome!

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