how do you set up this?
a car radiator contains 10 liters of 30% solution. how many liter will have to be replaced with pure anti-freeze if the resulting solution is to be 50%?

Question

how do you set up this?
a car radiator contains 10 liters of 30% solution. how many liter will have to be replaced with pure anti-freeze if the resulting solution is to be 50%?

hero · Answer

x = amount of pure antifreeze
y = total radiator fluid solution

Total liters of Radiator Fluid Solution:
10 + x = y

Total Percent Liters of Radiator Fluid Solution:
10(.30) + x = .50y

Solve this system:
       10 + x = y
10(.30) + x = .50y

anonymous · Answer

THANKS!!!

hero · Answer

What did you get for the values of x and y?