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An integration problem. (3/( x^3 + 3))dx Should I use integration by parts? Really confused.
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please check if statement is correct.
partial fraction decomp?
To do partial fraction you have to factor the denominator.
sum of cubes
Try that then.
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\[x ^{3}+3=\left( x+3^{\frac{ 1 }{ 3 }} \right)\left( x ^{2}+3^{\frac{ 1 }{ 3 }}x+3^{\frac{ 2 }{3 }} \right)\]
\[\frac{ 1 }{x ^{3}+3 }=\frac{ A }{x+3^{\frac{ 1 }{ 3 }} }+\frac{ Bx+C }{x ^{2}+3^{\frac{ 1 }{3 }}x+3^{\frac{ 2 }{3 }} }\] cross multiply and compare terms with like powers of x
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