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f(x)=6-5sin2(x-pi/3)
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state domain and range
Domain: All real numbers Range: -6<f(x)<6, this could also be all real numbers.
how?
-1<5sin2(x-pi/3)<1 5<6-5sin2(x-pi/3)<7
5 and 7 are in open intervals
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the solution sheet says D:(-oo,oo) R: [1,11]
oops sorry
6-5sin2(x-pi/3)..................... -1<=sin(x-pi/3)<=1 -5<=5sin(x-pi/3)<=5 ( on multiplying by 5) 5>=-5sin(x-pi/3)>=-5 ( on multiplying with -1) 11>=6-5sin(x-pi/3)>=1 (on adding 6)
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