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X^2-x=2 I know x=2 but i need the work
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\[x^{2} - x - 2 = 0\]
how about x=-1, it works too right ?
in general, if u have degree of 2, you will have 2 solutions that will work
you can factor and set each factor = 0 and solve for x.
use the quadratic formula on your second order polynomial in the form of ax^2 + bx + c = 0 \[x_{1and2} = \frac{ -b \pm \sqrt{b^2 - 4ac} }{ 2a}\]
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1st x from using the minus sign in plus-minus and 2nd x using the plus sign
\[x^2 - x - 2 = \left(x-2\right)\left(x+1\right)=0 \Rightarrow x-2 = 0 \text{ or } x+1 = 0\]
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