Question

Find the sum of all real solutions of the equation
x^2−16=3(x−4)^2.

Answer 1

\[x^{2}-16=3(x-4)^2\]
using difference of two squares we simplify left hand side
\[x^2-4^2=(x-4)(x+4)\]
\[(x-4)(x+4)=3(x-4)(x-4)\]
\[x+4=3(x-4)\]

Answer 2

I know that . But I got the Answer x=8 and its wrong .

Answer 3

that implies the above method is wrong,let me think of another way

Answer 4

Ok thanks , I'll wait :