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multiply\[6y \sqrt{7} * 2\sqrt{y}\]
\[6y\sqrt7\times 2\sqrt y=16y\sqrt{7y}\]
thats not the answer
\[12y \sqrt{7y}\]
yeah because \(2\times 6=12\) not \(16\) i would like to think of it as a typo
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lol
\[2\sqrt{11}*8\sqrt{22}\]
ok so first thing is can you simplify the radicals any further than they are already?
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