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Precalculus
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Find all values of x; tan x=1/√3
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see when tan x = 1/sqrt(3) tanx = tan (pi/6) now when tanx = tant then x= n*(pi)+t where n is any integer(0,+-1,+-2 ,+-3,....)
here t= pi/6
Okay thanks
yw
in particular u can substitute values for n
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Oh btw, how did you get pi/6
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