Question

sin2x=cosx on [0,2pi]

Answer 1

solve for x

Answer 2

sin 2x = cos x

sin 2x - cos x = 0

2 sin x cos x - cos x = 0

cos x (2 sin x - 1) = 0

cos x = 0 or sin x = 1/2


Between 0 and 2 pi :

x = pi/2 ; 3pi/2 ; pi/6 ; 5pi/6

I hope this is what you are looking for.

Answer 3

Thank you!! i got it xD

Answer 4

You're Welcome !