Question

x=5;
y=(++x)+(x++)+(++x);
what will the value of y???

Answer 1

++x is using a preincrement operator
what it does is it increments the value before the statement has been evaluated

x++ is using a post increment operator
what it does is it increments the operator after the statement has been evaluated

the answer would be
y= 6+5+6
y=17

Answer 2

/* used ch interpreter www.softintegration.com */
int x = 5;
int y = ( ++x ) + ( x++ ) + ( ++x );
printf( "%d\n", y );
20

Answer 3

20

Answer 4

++x=add 1 then write the value
x++=write the value then add1
y=(++x)+(x++)+(++x);
y=6+6+1+7
hope u got the point......:)

Answer 5

i think it will 21..but how????