A person walks first at a constant speed of 5.10 m/s along a straight line from point circle a to point circle b and then back along the line from circle b to circle a at a constant speed of 2.95 m/s.

a) What is the average velocity over the entire trip ?
b) what is the average speed over the entire trip?

Question

A person walks first at a constant speed of 5.10 m/s along a straight line from point circle a to point circle b and then back along the line from circle b to circle a at a constant speed of 2.95 m/s. 

a) What is the average velocity over the entire trip ?
b) what is the average speed over the entire trip?

anonymous · Answer

@saswamin
velocity = diplacement / time
The guy starts at point a and eventually returns back to point a.
Since the person did not really displace from his original location
displacement = 0

so the equation becomes v=0/t
or v=0