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Mathematics 7 Online
OpenStudy (anonymous):

find exact value of sin(-pi/3) w/o calculator

OpenStudy (amistre64):

you would have to pythag out an equilateral triangle

OpenStudy (amistre64):

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OpenStudy (anonymous):

|dw:1378235290486:dw|

OpenStudy (anonymous):

is it - sqrt3/2

OpenStudy (anonymous):

correct

OpenStudy (anonymous):

if i was not looking at my unit circle, how would I do this

OpenStudy (anonymous):

\[\sin \left( -\theta \right)=-\sin \theta \] in 1st all the t- ratios are positive sin and cosec is positive in 1st and 2nd quadrants in 3rd quadrant only tan and cot are positive. In 4th quadrant only cos and sec are positive.

OpenStudy (anonymous):

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