Question

midpoint H(13,8),X(-6,-6) i got two different answers the fist time i did i got 3.5, 1 then got this answer 2 , 1 which one is right
7

Answer 1

\(\normalsize{Midpoint}=\Large{(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})}\)

Answer 2

so is that right

Answer 3

3.5, 1 is right

Answer 4

Yes, but again exact forms are typically best.

Answer 5

so what one is it

Answer 6

You have the correct answer, but you have it in "approximate" form.

Answer 7

10.5 and -6 is it right

Answer 8

\(\normalsize{Midpoint}=\Large{(\frac{13+(-6)}{2},\frac{8+(-6)}{2})}\)

Answer 9

(3.5, 1) i was right the first time wow lol

Answer 10

That is what I said -_-

Answer 11

sorry