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Precalculus 16 Online
OpenStudy (anonymous):

PLEASEE PLEASEE HELPP!!

OpenStudy (anonymous):

Find the zeros of the function.f(x) = 9 x3 - 72 x2 + 135x

OpenStudy (anonymous):

-5 and -3 0, -5, and -3 5 and 3 0, 5, and 3

OpenStudy (anonymous):

\[f(x)=9x^3-72x^2+135x=9x(x^2-8x+15)\]in order to have f(x)=0 it has to be: x=0 and \[x^2-8x+15=0\rightarrow (x-5)(x-3)=0 \rightarrow x=5///x=3\]

OpenStudy (anonymous):

thank you soo muchh

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