Question

which equation will have the same solution as 3-5(2x+1=3(3+x)?

Answer 1

Solve for x:
2 x+1 = 3 (x+3)
Move everything to the left hand side.
Subtract 3 (x+3) from both sides of 2 x+1 = 3 (x+3):
1+2 x-3 (x+3) = 3 (x+3)-3 (x+3)
Look for two terms that sum to zero.
3 (x+3)-3 (x+3) = 0:
1+2 x-3 (x+3) = 0
Distribute -3 over x+3.
-3 (x+3) = -3 x-9:
1+2 x+-9-3 x = 0
Group like terms in 1+2 x-9-3 x.
Grouping like terms, 1+2 x-9-3 x = (2 x-3 x)+(1-9):
(2 x-3 x)+(1-9) = 0
Combine like terms in 2 x-3 x.
2 x-3 x = -x:
-x+(1-9) = 0
Evaluate 1-9.
1-9 = -8:
-x+-8 = 0
Isolate terms with x to the left hand side.
Add 8 to both sides:
-x+(-8+8) = 8
Look for two terms that sum to zero.
-8+8 = 0:
-x = 8
Solve for x.
Multiply both sides of -x = 8 by -1:
-(x)/(-1) = -8
Any nonzero number divided by itself is one.
(-1)/(-1) = 1:
Answer: |
| x = -8


So another equation with the same answer would be -x-8 = 0 right?