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Simplify the following. (2x/(x^2-6x+9)) - (1/(x+1)) - (8/(x^2-2x-3))
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\[\frac{ 2x }{ x^2 - 6x +9 } - \frac{ 1 }{ x + 1 } - \frac{ 8 }{ x^2 - 2x - 3 }\]
So let's do one step at a time. I would recommend you factor them all out first.
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