({x-8}/{x-7}) <=-3 FInd the interval i added 3 and tried to solve it but the systems marks me wrong.. i came up with (7,7.25]U[7.25,infinity)
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\[\frac{x-8}{x-7}\le-3~~~~~~~~~~~\text{(right away you know that }x\not=7)\\ ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~\text{(you also know that if }x<7,\text{ then the left side is positive})\\ x-8\le-3(x-7)\\ x-8\le-3x+21\\ 4x\le29\\ x\le\frac{29}{4}\] So it looks like you should be getting \((7,7.25]\).
damn, i was close, thanks for your response
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