Question

please help!!!when the expression 4x^2-3x-8 is divided by x-a the remainder is 2. Find the value of a

Answer 1

Easy,
p(x)=4x^2-3x-8
when x-a is a factor of p(x), then p(a) is equal to 2, so
p(a)=4a^2-3a-8=2

Solve for 4a^2-3a-8=2

Answer 2

what do you mean by solve for 4a^2-3a-8=2?

Answer 3

???

Answer 4

someone help!

Answer 5

\(\large{4a^2-3a-8=2}\)
Solve for a.

Answer 6

???

Answer 7

Solve for 'a',
Like this
4a^2-3a-8=2
subtract 2 to both sides
4a^2-3a-10=0
Then factor it

Answer 8

sorry,, my browser crashed,,

Answer 9

(-5 + -4a)(2 + -1a) = 0

Answer 10

next???

Answer 11

(4a-5)(a+2)

Answer 12

what's next??

Answer 13

get the roots??

Answer 14

Careful, its not (4a-5)(a+2)

Answer 15

sorry,,

Answer 16

xDD,,Careful, its not (4a+5)(a-2)

Answer 17

Okay then
(4a+5)(a-2)=0
a=-5/4 and a=2
done

Answer 18

ahha.,xDD sorry,, just copy pasted.. xDD

Answer 19

thanks,, so much.,