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Find the exact answer to this quadratic equation
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\[ 2x^2+5x=12\]
add a -12 to both sides of the equation to get: \[2x^2 +5x -12 = 0\] Factor the equation to get your solution for \[x \]
That's where I'm stuck. I'm either brain farting or nothing factors.
\[2x ^{2} + 8x - 3x - 12 = 0\] \[2x(x+4) -3(x+4) = 0\] \[(x+4) (2x-3) = 0\]
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