Question

Given the equation Square root of 2x plus 1 = 3, solve for x and identify if it is an extraneous solution.

x = 4, solution is extraneous

x = 4, solution is not extraneous

x = 5, solution is extraneous

x = 5, solution is not extraneous

Answer 1

So here is what we have:
\[\sqrt{2x}+1=3\]
So we can isolate like so:
\(\sqrt{2x}=2\)
\(2x=4\)
\(x=2\)
So. umm none of the above lol if that's the same starting equation, then none.