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sum 5k^2 +((7^(k+3))+(11^(2k+1)))/(13^(K+7)), k=1 to n+3
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I assume you're referring to 1^n+3 for the last part, correct?
\[\sum_{k=1}^{n+3}\]
thats what i mean by the last part the rest is the inside
Ahh, you're talking about Sigma Notation, okay, give me a sec!
thanks so much !
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ive got the first part of if the 5k^2 section
that rest is throwing me off
hey are you still trying to figure it out?
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