Question

how would I find the vertex and x intercepts for f(x)= 25-x^2

Answer 1

you can find the vertex by plugging into the equation -b/2a

Answer 2

so a=-1 and b=25

Answer 3

is c the y-intercept

Answer 4

for a parabola of that type, that is, with a squared "x" variable, you can get the vertex of it at \(\bf \left(-\cfrac{b}{2a}\quad, \quad-\cfrac{b^2}{4a}\right)\)

Answer 5

\(\bf \left(-\cfrac{b}{2a} \quad , \quad c-\cfrac{b^2}{4a}\right)\) rather