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OpenStudy (anonymous):
the binomials (x-2) and (2x+3) are the factors of which polynomial ? A) 2x^2-6 ; B) 2x^2-x-6 ; C)2x^2+x-6 OR D) 2x^2+7x-6 ?
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OpenStudy (raden):
just multiply of (x-2)(2x+3), can you expand this ?
OpenStudy (anonymous):
idk the choices are A) 2x^2-6 B) 2x^2-x-6 C) 2x^2+x-6 D) 2x^2+x-6
OpenStudy (raden):
use the FOIL method (x-2)(2x+3)
multiplying the First terms, x * 2x = 2x^2
multiplying the Outside terms, x * 3 = 3x
multiplying the Inside terms, -2 * 2x = -4x,
and multiplying the Last terms, -2 * 3 = -6
ow add them, becomes 2x^2 + 3x + (-4x) + (-6) = 2x^2 -x -6
OpenStudy (raden):
* now
OpenStudy (anonymous):
ohhh I think its 2x^2-x-6
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OpenStudy (raden):
yes
OpenStudy (anonymous):
okay thank youu
OpenStudy (raden):
you're welcome
OpenStudy (anonymous):
I need your help again
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OpenStudy (raden):
i'll try, what your question
OpenStudy (anonymous):
which is NOT a factor of 2x^2-32 ?
A) x^2-32 B) 2 C) x-4 D) x^2-16
OpenStudy (raden):
the factors of 2x^2-32 are
2(x^2 - 16) = 2(x-4)(x+4)
so,we have the factors : 2, x-4, x+4, x^2-16
i didnt see the x^2-32 be one of the factor
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