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3x^1/2-7x^1/4+1=0
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\[3x ^{1/2}-7x ^{1/4}+1=0\]
y = x^(1/4) so 3y^2 -7y+1=0 helps ?
Yes sir thanks, do you use the factoring formula?
3y^2 -7y+1=0 you can solve it using quadratic formula
Thanks again, do I need to multiply it to the 4th power?
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now when you found y you need to raise it to the 4th power as you said so you will get x.
7+√37/(6)^4, 7-√37/((6^4
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