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6x-4 < -34 or 3x + 10>10 solve
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I will do one, and you can do the other, sound ok?
k
\(6x-4<-34\) First we add 4 to both sides. \(4+(6x-4)<(-34)+4\) Then we simplify. \(6x<-30\) Then you divide by the coefficient on the variable. \(\color{red}{\text{NOTE: If the coefficient is negative, you must switch the sign to it's opposite}}\) \(x<-5\) Now, I want you to try the other! :)
then the next one would be 0? correct
or 6/ 2 over 3
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It would be zero :)
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