Question

The length of a rectangle is 2 cm less than 7 times the width . The perimeter is 60 . Find the width and length .

Answer 1

7 times "something" => 7(something)
2 less than "something" => 2 - (something)

2 less than 7 times "something" => 2-7(something)

perimeter is just the SUM OF THE SIDES

a rectangle has 4 SIDES, 2 equal lengths, 2 equal width

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if the "width" is say "w", the length will be 2-7w

W = w
L = 2-7w

perimiter is W + W + L + L => 2W + 2W = > 2w + 2(2-7w)

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we know the perimeter is 60, thus \(\bf perimeter = W + W + L + L => 2W + 2W = > \color{blue}{2w + 2(2-7w)}\\\qquad \\
60 = 2w + \color{blue}{2(2-7w)}\)

solve for "w"