Question

How do you solve this

4x^2=8x-1

Finding the roots

Answer 1

move everything to once side and factor it (or use the quadratic formula).

Answer 2

I did that but my answer does not match the textbook

Answer 3

\(4x^2=8x-1\)
\(4x^2-8x+1=0\)

use the quadratic formula

Answer 4

Hmm, Why cannt it be -4x^2... you have moves the other digits over is there a reason

Answer 5

it can be \(4x^2−8x+1=0\) or \(-4x^2+8x-1=0\)

you need to plug into the quadratic formula now

Answer 6

close this please