Two perpendicular chords divide a circle with a radius of 13 cm into four parts. If the perpendicular distances of both chords are 5 cm each from the center of the circle, find the area of the smallest part.

Question

anonymous · Answer

|dw:1378430352944:dw|

anonymous · Answer

first cut the square into 2 triangles and find the hypotenuse then subtract that from 13cm to find the middle line of the triangle in the smallest space

anonymous · Answer

next you would draw a line from the top right of the square to where the question mark is. you know 2 sides of that triangle so solve for the last side and subtract by 5

anonymous · Answer

OH, got it,,, i got this :)

anonymous · Answer

|dw:1384302010469:dw| is this the one I'm finding?