Question

g(t)={6-pt ,t. {q+e-2t ,t=0. Is differentiable at t=0,what is thevalue of g(q-p)?

Answer 1

Can't read it...

Answer 2

This doesn't make sense...\[
g(t) = \begin{cases}
6-pt&t\\
q+e-2t&t=0
\end{cases}
\]

Answer 3

g(t) = {6-pt, t>0; q+e^(-2t), t=<0}