An airplane starts from rest and accelerates at 5.99 m/s2. What is its speed at the end of a 500-m runway?

Question

anonymous · Answer

$$S=\frac{ 1 }{ 2 }at^2\rightarrow t=\sqrt{\frac{ 2S }{a }}$$$$v=at=a \sqrt{\frac{ 2S }{ a }}=\sqrt{2aS}$$where a=5.99 and S=500

goformit100 · Answer

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