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If log_sinx(cosx)=1/2, and 0
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lets apply the definition, \(\log_ab=c \implies b=a^c\) you knew this, right ?
what will log_sinx(cosx)=1/2 simplify to ?
Sinx^1/2=cosx?
yup, now square both sides
Sinx= (cosx)^2
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try to bring everything in sin x
how would u write cos^2 x in terms of sin x ?
cos( 2x) = 1 - sin^2( x)
you meant cos^2x = 1-sin^2 x then its correct :) so sin x = 1-sin^2 x can you now solve for sin x ? its just a quadratic
still here ? stuck or trying ?
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Sin^2x+sinx -1=0 is this right?
yup. its like y^2 + y-1 =0 where y= sin x a simple quadratic equation, solve for y, you would have solved for sin x
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