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Determine whether the equation defines y as a function of x. 8x^2+y^2=1 walk me through do not just answer im soo confused...
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for any given x value, how many y values are possible?
I know....
lets say x=2. solve for y
its ummmmm
I'll guess 2
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@Zaqewwe can you solve \[8x^2+y^2=1\] for \(y\)? or, do you know what the graph looks like?
seem to have alot of... "hour ago" posts up this morning
maybe posted and then went back to sleep
y=square root of -8x^2 + 1
@satellite73
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