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What is the equation of the line between the points (2, 8) and (3, -2)?
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first find slope m
(y-y1) =m(x-x1) where m is the slope = (y2-y1) / (x2-x1)
so the slope is -10?
yes,
now you have a point and slope use y-y1 = m (x-x1) use x1,y1 as any one of the 2 points given
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so then it would be -2-8=-10(3-2) correct?
Nope, |dw:1378647664578:dw| y-8=-10(x-2)
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