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OpenStudy (anonymous):
What is the average kinetic energy of 1 mole of a gas at 125 Kelvin? (R = 8.314 J/K-mol) Answer 1.04 x 103 J 3.12 x 103 J 1.56 x 103 J 1.77 x 103 J
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OpenStudy (aaronq):
\(K.E._{avg}=\dfrac{3}{2}kT\)
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