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Segment AB bisects Segment CD at point M, Segment CD bisects segment AB at Point M and AB equals 4*CM . What is the relationship between AM and CD? Help
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is there a drawing to this?
|dw:1378499668401:dw| M is the middle of both segments. If AB = 4CM and CM is half CD then AB=2CD. Since M is also the middle of AB then AB=2AM. From those 2 rationalizations you can deduce AM=CD.
Thanks I was on the right track but had a brain fart and had thought that AB = 8CD now that i see what u wrote makes sense
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