Ask your own question, for FREE!
Mathematics 18 Online
OpenStudy (anonymous):

Factor x^2+xi-i-x=0.

OpenStudy (anonymous):

\[x^2+xi-i-x=0\] This might look nicer like so: \[x^2+xi-x-i\] And we can simplify: \[x(x+i)-1(x+1)\] And group: \[(x-1)(x+i)\]

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Latest Questions
Arriyanalol: i need help
1 day ago 7 Replies 1 Medal
Arriyanalol: CONGRATS to me
1 day ago 8 Replies 2 Medals
Legomaster346: What colleges are good that are near Arab Alabama?
1 week ago 5 Replies 0 Medals
Arriyanalol: i need help
1 week ago 6 Replies 2 Medals
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!