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Mathematics 16 Online
OpenStudy (anonymous):

Factor x^2+xi-i-x=0.

OpenStudy (anonymous):

\[x^2+xi-i-x=0\] This might look nicer like so: \[x^2+xi-x-i\] And we can simplify: \[x(x+i)-1(x+1)\] And group: \[(x-1)(x+i)\]

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