Question

PLEASE HELP.

Find the value of Q in the following system so that the solution to the system is {(x,y):x-3y=4}
x-3y=4
2x+Qy=8

Answer 1

-6 I think,
2x/x = 2
8/4 = 2
so Qy/-3y should be 2:
-6y/-3y=2

Answer 2

@ali1029 , got it?

Answer 3

if Q is anything but -6, the solution to the system is a point. If Q is -6, the solution to the system is the line specified.