Question

Find the angle between the given vectors to the nearest tenth of a degree.

u = <-5, -4>, v = <-4, -3>

Answer 1

\[
\|\mathbf u \cdot \mathbf v\| = \|\mathbf u \| \|\mathbf v\|\cos(\theta)
\]

Answer 2

\[
\theta = \cos^{-1}\left(\frac{\|\mathbf u \cdot \mathbf v\|}{\|
\mathbf u\|\|\mathbf v\|}\right)
\]

Answer 3

This is one way of doing it.

Answer 4

\[
\tan\theta _{\mathbf u} =\frac { \mathbf u_y }{\mathbf u_x}
\]

Answer 5

\[
\theta = |\theta_{\mathbf u} - \theta_{\mathbf v}|
\]

Answer 6

I got -2.

Answer 7

It's off because these are my choices:
-9.1°

1.8°

0.9°

11.8°