How do you do this problem? 32x-8/4 (divided by 4) And 24m-6 divided by -3
the first equation would look like this, right? \[\frac{ 32x-8 }{4 }\]
Yes
Same setup for the second equation too
then you would solve it like this:\[\frac{ 32x-8 }{ 4}*4\] ( the fours cancel each other out) \[32x-8=0\] (add 8 to both sides) \[32x=8\] then divide both sides by 32 to get your answer
K thank
you're welcome. You do the other problem the same way.
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