Question

The real solutions of
x^2-4x-2=0. Show all steps please!

Answer 1

You have to use the quadratic formula if I'm not mistaken

Answer 2

Yeah I know that much but I'm not sure how to do it

Answer 3

I'll get you started


\[\Large x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\]


\[\Large x = \frac{-(-4)\pm\sqrt{(-4)^2-4(1)(-2)}}{2(1)}\]


\[\Large x = \frac{4\pm\sqrt{16-(-8)}}{2}\]

Answer 4

Yea.. What Jim did.. :/

Answer 5

Thanks so much!!!

Answer 6

np

Answer 7

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