Question

@ganeshie8

Answer 1

find G(F(x))

Answer 2

G(F(x)) = G(\(\sqrt{x-6}\))

= \(\large \sqrt{\frac{1}{\sqrt{x-3}-3}}\)

Answer 3

you need to find the domain of that function

Answer 4

do we need to findx?

Answer 5

since you have square root, the thing inside must be >=0
also since the botom cannot equal 0,

we can have this :-

\(\sqrt{x-3} - 3 > 0\)

Answer 6

solve x

Answer 7

**thats sqrt(x-6) actually


\(\sqrt{x-6} - 3 > 0\)

\(\sqrt{x-6} > 3\)

Answer 8

an u solve x ? :)

Answer 9

i got d

Answer 10

yes domain is, x > 15

Answer 11

good work !