Question

The length of a rectangle is three more than twice the width. If the perimeter is 72 inches, find the dimensions of the rectangle.

Answer 1

The width is your base so width = x. The length of your rectangle is three more than twice the width so length = 2x + 3. Now, your perimeter is the sum of all four sides of the rectangle, so x + x + (2x + 3) + (2x + 3) = 72. Solve for x and continue from there.

Answer 2

X+ 6x = 72
X = 11 ?

Answer 3

So now you know that your width is 11, just solve for your length and you have both dimensions

Answer 4

so if x=11, do I plug it back into the long equation?