The sum of two numbers is 81. The difference of twice one and three times the other is 62. Find the numbers. How do i do this problem?!?!?!
Using Systems of linear equations but how?!?!
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hehe
try: let x = the first number let y = the second number Then follow the statements to make your equation. Let me know if you need more hints
so let's call this 2 numbers "a" and "b" their sum is 81 => a + b = 81 twice one and three times the other is 62. 2a 3b = 62 so a + b = 81 2a + 3b = 62 so, there :)
ohh.. the difference... shoot...ok
so let's call this 2 numbers "a" and "b" their sum is 81 => a + b = 81 twice one and three times the other is 62. 2a - 3b = 62 so a + b = 81 2a - 3b = 62 so, there :)
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