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Mathematics 20 Online
OpenStudy (anonymous):

e^3x+1 = 100

OpenStudy (anonymous):

e^3x+1-1=100-1 ln(e^3x)=ln(99) 3x=ln(99) x=1/3*ln(99)

OpenStudy (anonymous):

Are you sure let me re type it e^(3x+1) = 100? I don't think I can do that to the 1

OpenStudy (anonymous):

Ah alright, in that case it'd be like so: ln(e^(3x+1)) = ln(100) 3x+1 = ln(100) x = (ln(100)-1)*1/3

OpenStudy (anonymous):

Thank you, what kind of questions are these called? I wanna look these up, but can't find anything by just typing the problem. And I wouldn't want to bother you all night.

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