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expand sinx in powers of (x- pi/2) and then using it to approximate sin 91 degree!! Help plzzz!!
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i already expanded the series! but cannot understand how to find the value of sin 91 degree!!
\[sinx = 1-\frac{ (x-\frac{ \Pi }{ 2 })^{2}}{2!}+\frac{ (x-\frac{ \Pi }{ 2 })^{4}}{4!}-......\]
@wio help plzzz!!
Um, \(x=91\)
but it is in degrees!! how to put the value??
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\[ 91^\circ = \frac{91\pi}{180} \]
yeah then what would be the value?? would it be 1.588 ??
Just plug it in.
thanks man!! appreciate it!!
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