Question

Could somebody please help me with the following question:

Answer 1

i have attached the question

Answer 2

(a). see the triangle of AOP (right triangle), use the value of tan25
tan25 = OP/AO
tan25 = h/AO
solve for AO

(b). in triangle of BOP (right triangle), use the value of tan33
tan33 = OP/BO
tan33 = h/BO
solve for BO

(c). look at the triangle of AOB (also right triangle )
use the pythagorean theorem :
(AO)^2 + (BO)^2 = (AB)^2
(still waiting your answer in part (a) and (b))

continue it, @smsmsmsm

Answer 3

dont forget, a calculator :)

Answer 4

Thank you RadEn :)

Answer 5

you're welcome