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Mathematics 23 Online
OpenStudy (anonymous):

solve m^2-12=m

OpenStudy (akashdeepdeb):

Do it just like a normal quadratic equation is solved. m2-m-12=0 Then find the values of m. Understood? :)

OpenStudy (uri):

Do you understand? @_ambitiousiam

OpenStudy (anonymous):

no not at all @uri

OpenStudy (dls):

\[\LARGE m^2-12=m\] \[\LARGE m^2-m-12=0\] \[\LARGE m^2-4m+3m-12=0\] Do you know how to factor further?I gave many hints already :)

OpenStudy (dls):

take something common from first 2 terms and something' from the other 2 terms

OpenStudy (anonymous):

thank you now i understand @DLS

OpenStudy (dls):

m=??

OpenStudy (uri):

@_ambitiousiam Can you solve it further? What is common in this?|dw:1378654028172:dw|

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